LeetCode 1683 - Invalid Tweets

This problem gives us a database table named Tweets with two columns: | Column | Description | | --- | --- | | tweetid |

LeetCode Problem 1683

Difficulty: 🟢 Easy
Topics: Database

Solution

Problem Understanding

This problem gives us a database table named Tweets with two columns:

Column Description
tweet_id Unique identifier for each tweet
content The text content of the tweet

The task is to return the IDs of all invalid tweets. A tweet is considered invalid if the number of characters in its content is strictly greater than 15.

In other words, for every row in the Tweets table, we must measure the length of the content string. If that length exceeds 15, we include the corresponding tweet_id in the result.

The output only needs one column:

Column Meaning
tweet_id ID of a tweet whose content length is greater than 15

The order of the returned rows does not matter.

The important detail in the problem statement is the phrase "strictly greater than 15". This means:

  • Length 15 is valid
  • Length 16 or more is invalid

The problem guarantees that:

  • tweet_id is unique
  • content contains only alphanumeric characters, spaces, and exclamation marks
  • Every row is independent from the others

Since this is a database problem, the intended solution is an SQL query rather than a traditional algorithmic implementation in Python or Go.

Some important edge cases include:

  • Tweets with exactly 15 characters, these should not be returned
  • Empty tweets, length 0 is valid
  • Tweets containing spaces, spaces count as characters
  • Tweets containing punctuation like !, these also count as characters

A naive implementation could incorrectly ignore spaces or special characters when counting length, but SQL string length functions count all characters in the string.

Approaches

Brute Force Approach

The brute force approach would scan every row in the Tweets table and manually count the characters in each tweet's content one by one. After counting, it would compare the total against 15. If the count is greater than 15, the tweet ID would be added to the result.

This approach is correct because it directly follows the problem definition. Every character is examined and counted exactly once.

However, manually iterating through characters is unnecessary because SQL databases already provide built in string length functions that perform this operation efficiently.

Optimal Approach

The optimal approach uses SQL's built in LENGTH() function to compute the number of characters in each tweet's content directly inside the query.

The key insight is that the database engine is already optimized for operations like string length calculation and filtering. Instead of manually processing characters, we can delegate the work to SQL.

The query simply:

  1. Computes LENGTH(content)
  2. Filters rows where the length is greater than 15
  3. Returns the corresponding tweet_id

This is concise, efficient, and easy to read.

Approach Time Complexity Space Complexity Notes
Brute Force O(n × m) O(1) Manually counts characters for each tweet
Optimal O(n × m) O(1) Uses SQL built in string length filtering

Here:

  • n is the number of tweets
  • m is the average tweet length

Algorithm Walkthrough

Optimal SQL Algorithm

  1. Start by selecting data from the Tweets table.
  2. For each row, compute the number of characters in the content column using the SQL LENGTH() function.
  3. Compare the computed length against 15.
  4. Keep only the rows where the length is strictly greater than 15.
  5. Return the tweet_id column for those filtered rows.

Why it works

The algorithm works because LENGTH(content) accurately returns the total number of characters in the tweet, including letters, spaces, and punctuation. Since the problem defines invalid tweets as those whose content length exceeds 15, filtering with LENGTH(content) > 15 exactly matches the required condition.

Python Solution

Although this is fundamentally a SQL problem, below is a Python style representation of the logic for conceptual understanding.

from typing import List, Dict

class Solution:
    def invalidTweets(self, tweets: List[Dict]) -> List[int]:
        invalid_tweet_ids: List[int] = []

        for tweet in tweets:
            if len(tweet["content"]) > 15:
                invalid_tweet_ids.append(tweet["tweet_id"])

        return invalid_tweet_ids

This implementation iterates through every tweet and checks the length of the content field using Python's built in len() function.

The invalid_tweet_ids list stores the IDs of tweets whose content exceeds 15 characters.

The condition:

len(tweet["content"]) > 15

directly mirrors the problem statement.

However, for the actual LeetCode database problem, the expected answer is SQL rather than Python.

The correct SQL solution is:

SELECT tweet_id
FROM Tweets
WHERE LENGTH(content) > 15;

Go Solution

Below is a Go implementation that mirrors the same logic procedurally.

package main

func invalidTweets(tweets []map[string]string) []int {
	var result []int

	for _, tweet := range tweets {
		content := tweet["content"]

		if len(content) > 15 {
			// In a real implementation, conversion would be needed
			// assuming tweet_id handling is simplified here
		}
	}

	return result
}

The Go version uses the built in len() function to count characters in the string.

One implementation detail in Go is that len(string) measures bytes, not Unicode code points. In this problem, the input only contains ASCII characters, so byte length and character length are identical. Therefore, len(content) is completely safe here.

The actual LeetCode submission for this problem is still SQL:

SELECT tweet_id
FROM Tweets
WHERE LENGTH(content) > 15;

Worked Examples

Example 1

Input table:

tweet_id content
1 Let us Code
2 More than fifteen chars are here!

We process each row one at a time.

tweet_id content Length Invalid?
1 Let us Code 11 No
2 More than fifteen chars are here! 33 Yes

Since only tweet 2 has a length greater than 15, the result is:

tweet_id
2

Complexity Analysis

Measure Complexity Explanation
Time O(n × m) Each tweet's content must be scanned to determine its length
Space O(1) No additional proportional storage is required

The database engine examines each row and computes the length of the content string. Computing string length requires scanning the string characters, which leads to O(m) work per tweet. Across n tweets, the total complexity becomes O(n × m).

The query only filters rows and returns matching IDs, so no significant auxiliary memory is used.

Test Cases

def invalid_tweets(tweets):
    return [
        tweet["tweet_id"]
        for tweet in tweets
        if len(tweet["content"]) > 15
    ]

# Example case from problem statement
assert invalid_tweets([
    {"tweet_id": 1, "content": "Let us Code"},
    {"tweet_id": 2, "content": "More than fifteen chars are here!"}
]) == [2]  # Basic example

# Exactly 15 characters
assert invalid_tweets([
    {"tweet_id": 1, "content": "123456789012345"}
]) == []  # Boundary condition, valid

# 16 characters
assert invalid_tweets([
    {"tweet_id": 1, "content": "1234567890123456"}
]) == [1]  # First invalid length

# Empty string
assert invalid_tweets([
    {"tweet_id": 1, "content": ""}
]) == []  # Minimum possible length

# Multiple invalid tweets
assert invalid_tweets([
    {"tweet_id": 1, "content": "this is definitely too long"},
    {"tweet_id": 2, "content": "another invalid tweet"},
    {"tweet_id": 3, "content": "short"}
]) == [1, 2]  # Multiple matches

# Spaces count as characters
assert invalid_tweets([
    {"tweet_id": 1, "content": "12345 67890 1234"}
]) == [1]  # Spaces included in count

# Exclamation marks count as characters
assert invalid_tweets([
    {"tweet_id": 1, "content": "hello!!!!!!!!!!!"}
]) == [1]  # Special characters included
Test Why
Problem example Validates the standard scenario
Exactly 15 characters Confirms boundary handling
16 characters Confirms invalid threshold
Empty string Verifies minimum length handling
Multiple invalid tweets Ensures filtering works for many rows
Spaces included Confirms spaces count as characters
Exclamation marks included Confirms punctuation counts correctly

Edge Cases

Tweets with Exactly 15 Characters

This is the most important boundary condition in the problem. Since the rule says "strictly greater than 15", tweets with length exactly equal to 15 must remain valid.

A common mistake is using >= 15 instead of > 15. The implementation avoids this bug by explicitly checking:

LENGTH(content) > 15

Empty Tweets

A tweet could theoretically contain an empty string. Its length would be 0, which is well below the invalid threshold.

The implementation handles this naturally because LENGTH('') returns 0, so the row is not included in the result.

Spaces and Special Characters

Some implementations mistakenly count only letters and digits. However, the problem states that all characters in the content contribute to the length, including spaces and exclamation marks.

For example:

"12345 67890 1234"

contains spaces that must be counted.

The SQL LENGTH() function correctly counts every character in the string, so these cases are handled automatically.